tolong bantu jawab kak.
[tex]\scriptsize \boxed{\begin{aligned}\sf \int_ {1}^{2}( {9x}^{2} - 6x + 3) \: dx &=\sf \int 9{x}^{2} \: dx - \int 6x \: dx + \int 3 \: dx\\ \sf &=\sf \frac{9 {x}^{2 + 1} }{2 + 1} - \frac{6 {x}^{1 + 1} }{1 + 1} + 3x \\ \sf &= \sf \frac{ {9x}^{3} }{3} - \frac{ {6x}^{2} }{2} + 3x \\ \sf &=\sf {3x}^{3} - {3x}^{2} + 3x\\ \sf &=\sf {3x}^{3} - {3x}^{2} + 3x \: |_ {1}^{2}\\ \sf &=\sf (3. {2}^{3} - 3. {2}^{2} + 3.2) - 3. {1}^{3} - 3. {1}^{2} + 3.1\\ \sf &=\sf 24 - 12 + 6 - 3 - 3 + 3\\ \sf &=\sf 15\end{aligned}}[/tex]
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