Matematika Sekolah Menengah Atas Tolong bantu menjawab kak..​

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[tex] \boxed{\begin{aligned} \sf f(x)&=\sf 3 {x}^{3} + \frac{5}{2 } {x}^{2} - 2x + 25 \end{aligned}}[/tex]

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PEMBAHASAN

Diketahui:

[tex]{\begin{aligned}\sf \bull \: \: f(x) &=\sf \int( {9x}^{2} + 5x - 2) \: dx\\ \sf &=\sf \frac{9}{2 + 1} {x}^{2 + 1} + \frac{5}{1 + 1} {x}^{1 + 1} - 2x + C \\ \sf &= \sf \frac{9}{3} {x}^{3} + \frac{5}{2} {x}^{2} - 2x + C \\ \sf f(x)&=\sf 3 {x}^{3} + \frac{5}{2 } {x}^{2} - 2x + C \end{aligned}}[/tex]

[tex]\sf \bull \: \: f(2) = 5[/tex]

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Ditanyakan:

f(x) = ___?

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Penyelesaian:

[tex]\begin{aligned}\sf f(x)&=\sf \sf 3 {x}^{3} + \frac{5}{2 } {x}^{2} - 2x + C\\ \sf f(2)&=\sf 3(2 {)}^{3} + \frac{5}{2} ( {2)}^{2} - 2(2) + C \\ \sf 5&= \sf 3(8) + \frac{5}{2} (4) - 4 +C \\ \sf 5&=\sf 24 + 10 - 4 + C\\ \sf 5&=\sf 30 + C\\ \sf C&=\sf 30 - 5\\ \sf C&=\sf 25\end{aligned}[/tex]

Sehingga:

[tex]\sf f(x)=\sf 3 {x}^{3} + \dfrac{5}{2 } {x}^{2} - 2x + C [/tex]

[tex] \boxed{\begin{aligned} \sf f(x)&=\sf 3 {x}^{3} + \frac{5}{2 } {x}^{2} - 2x + 25 \end{aligned}}[/tex]

Jawaban:

f(x)= 3x³+5/2x²-2x+25

Penjelasan dengan langkah-langkah:

Integrasikan:

f(x)= 9/3x³+ 5/2x²-2x+C

f(x)= 3x³+5/2x²-2x+C

f(2)= 5

3(2)³+5/2(2)²-2(2)+C= 5

3(8)+5/2(4)-4+C= 5

24+3/2(4)+C= 5

24+6-C= 5

30-C=5

C= 25

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